At a carnival a patron can purchase an admission ticket plus 20 rides for $29.50 or an admission ticket and 8 rides for $14.50. Assuming the carnival operators price consistently, what is the cost of the admission ticket only?
Correct Answer: C
Ticket Cost = (Admission Cost) + (Ride Cost)(Number of Rides)
- The basic equation for this problem is:
Ticket Cost = (Admission Cost) + (Ride Cost)(Number of Rides) - Let A = the cost of admission
Let R = the cost per ride - Taken together:
Ticket Cost = A + R(Number of Rides) - From the information given, derive two equations:
29.5 = A + 20R
14.5 = A + 8R - Subtract the lower equation from the upper equation:
29.5 - 14.5 = A - A + 20R - 8R
15 = 12R
R = 15/12 = 5/4 - Substitute R back into one of the two equations:
14.5 = A + 8(5/4)
14.5 = A + 10
4.5 = A
No comments:
Post a Comment